Problem Link

Description


Given two numbers, hour and minutes, return the smaller angle (in degrees) formed between the hour and the minute hand.

Answers within 10-5 of the actual value will be accepted as correct.

 

Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

 

Constraints:

  • 1 <= hour <= 12
  • 0 <= minutes <= 59

Solution


Python3

class Solution:
    def angleClock(self, hour: int, minutes: int) -> float:
        h = (hour%12) * 30 + (minutes/60 * 30)
        
        m = minutes/60 * 360
        
        angle = abs(h-m)
        
        if angle > 180:
            angle = 360 - angle
        
        return angle