Problem Link

Description


Given an n x n integer matrix grid, return the minimum sum of a falling path with non-zero shifts.

A falling path with non-zero shifts is a choice of exactly one element from each row of grid such that no two elements chosen in adjacent rows are in the same column.

Β 

Example 1:

Input: grid = [[1,2,3],[4,5,6],[7,8,9]]
Output: 13
Explanation: 
The possible falling paths are:
[1,5,9], [1,5,7], [1,6,7], [1,6,8],
[2,4,8], [2,4,9], [2,6,7], [2,6,8],
[3,4,8], [3,4,9], [3,5,7], [3,5,9]
The falling path with the smallest sum isΒ [1,5,7], so the answer isΒ 13.

Example 2:

Input: grid = [[7]]
Output: 7

Β 

Constraints:

  • n == grid.length == grid[i].length
  • 1 <= n <= 200
  • -99 <= grid[i][j] <= 99

Solution


Python3

class Solution:
    def minFallingPathSum(self, grid: List[List[int]]) -> int:
        rows, cols = len(grid), len(grid[0])
 
        for i in range(1, rows):
            prev = heapq.nsmallest(2, grid[i - 1])
            for j in range(cols):
                grid[i][j] += (prev[1] if grid[i - 1][j] == prev[0] else prev[0])
 
        return min(grid[-1])