Problem Link

Description


You are given an array of strings words (0-indexed).

In one operation, pick two distinct indices i and j, where words[i] is a non-empty string, and move any character from words[i] to any position in words[j].

Return true if you can make every string in words equal using any number of operations, and false otherwise.

 

Example 1:

Input: words = ["abc","aabc","bc"]
Output: true
Explanation: Move the first 'a' in words[1] to the front of words[2],
to make words[1] = "abc" and words[2] = "abc".
All the strings are now equal to "abc", so return true.

Example 2:

Input: words = ["ab","a"]
Output: false
Explanation: It is impossible to make all the strings equal using the operation.

 

Constraints:

  • 1 <= words.length <= 100
  • 1 <= words[i].length <= 100
  • words[i] consists of lowercase English letters.

Solution


Python3

class Solution:
    def makeEqual(self, words: List[str]) -> bool:
        N = len(words)
        counter = Counter()
 
        for word in words:
            for x in word:
                counter[x] += 1
        
        return all(v % N == 0 for v in counter.values())