Description
null
Solution
TypeScript
function areDeeplyEqual(o1: any, o2: any): boolean {
// All equal values and same objects are eliminated
if (o1 === o2) return true;
// If any of o1 or o2 is not an object, they are different values
if (typeof o1 != 'object' || typeof o2 != 'object') return false;
// Both of them should be objects or arrays
if (Array.isArray(o1) !== Array.isArray(o2)) return false;
// Both should have same keys, in case of indexes this will return indexes
if (Object.keys(o1).length != Object.keys(o2).length) return false;
// Check if all values against keys of o1 and o2 are deeply equal.
// If number of keys are same, then at a different key in objects would mean at least
// 1 value against the key of o2 will be undefined
for (const key in o1) {
if (!areDeeplyEqual(o1[key], o2[key])) return false;
}
// All checks passed
return true;
};