Problem Link

Description


Given two integer arrays nums1 and nums2, sorted in non-decreasing order, return the minimum integer common to both arrays. If there is no common integer amongst nums1 and nums2, return -1.

Note that an integer is said to be common to nums1 and nums2 if both arrays have at least one occurrence of that integer.

 

Example 1:

Input: nums1 = [1,2,3], nums2 = [2,4]
Output: 2
Explanation: The smallest element common to both arrays is 2, so we return 2.

Example 2:

Input: nums1 = [1,2,3,6], nums2 = [2,3,4,5]
Output: 2
Explanation: There are two common elements in the array 2 and 3 out of which 2 is the smallest, so 2 is returned.

 

Constraints:

  • 1 <= nums1.length, nums2.length <= 105
  • 1 <= nums1[i], nums2[j] <= 109
  • Both nums1 and nums2 are sorted in non-decreasing order.

Solution


Python3

class Solution:
    def getCommon(self, nums1: List[int], nums2: List[int]) -> int:
        M, N = len(nums1), len(nums2)
        j = 0
 
        for i in range(M):
            while j < N and nums2[j] < nums1[i]:
                j += 1
            
            if j == N: break
 
            if nums1[i] == nums2[j]:
                return nums1[i]
        
        return -1