Problem Link

Description


Given an integer array nums of positive integers, return the average value of all even integers that are divisible by 3.

Note that the average of n elements is the sum of the n elements divided by n and rounded down to the nearest integer.

 

Example 1:

Input: nums = [1,3,6,10,12,15]
Output: 9
Explanation: 6 and 12 are even numbers that are divisible by 3. (6 + 12) / 2 = 9.

Example 2:

Input: nums = [1,2,4,7,10]
Output: 0
Explanation: There is no single number that satisfies the requirement, so return 0.

 

Constraints:

  • 1 <= nums.length <= 1000
  • 1 <= nums[i] <= 1000

Solution


Python3

class Solution:
    def averageValue(self, nums: List[int]) -> int:
        res = 0
        count = 0
        
        for x in nums:
            if x % 3 == 0 and x % 2 == 0:
                res += x
                count += 1
                
        if count == 0: return 0
        
        return res // count