Problem Link

Description


A string s is called good if there are no two different characters in s that have the same frequency.

Given a string s, return the minimum number of characters you need to delete to make s good.

The frequency of a character in a string is the number of times it appears in the string. For example, in the string "aab", the frequency of 'a' is 2, while the frequency of 'b' is 1.

Β 

Example 1:

Input: s = "aab"
Output: 0
Explanation: s is already good.

Example 2:

Input: s = "aaabbbcc"
Output: 2
Explanation: You can delete two 'b's resulting in the good string "aaabcc".
Another way it to delete one 'b' and one 'c' resulting in the good string "aaabbc".

Example 3:

Input: s = "ceabaacb"
Output: 2
Explanation: You can delete both 'c's resulting in the good string "eabaab".
Note that we only care about characters that are still in the string at the end (i.e. frequency of 0 is ignored).

Β 

Constraints:

  • 1 <= s.length <= 105
  • sΒ contains only lowercase English letters.

Solution


Python3

class Solution:
    def minDeletions(self, s: str) -> int:
        N = len(s)
        counter = Counter(s)
        curr = inf
        res = 0
 
        for v in sorted(counter.values(), reverse = 1):
            if v > curr:
                res += v - curr
                v = curr
 
            curr = max(v - 1, 0)
 
        return res