Description
A sequence of numbers is called an arithmetic progression if the difference between any two consecutive elements is the same.
Given an array of numbers arr, return true if the array can be rearranged to form an arithmetic progression. Otherwise, return false.
Example 1:
Input: arr = [3,5,1] Output: true Explanation: We can reorder the elements as [1,3,5] or [5,3,1] with differences 2 and -2 respectively, between each consecutive elements.
Example 2:
Input: arr = [1,2,4] Output: false Explanation: There is no way to reorder the elements to obtain an arithmetic progression.
Constraints:
2 <= arr.length <= 1000-106 <= arr[i] <= 106
Solution
Python3
class Solution:
def canMakeArithmeticProgression(self, arr: List[int]) -> bool:
n = len(arr)
arr.sort()
diff = arr[1] - arr[0]
for i in range(2, n):
d = arr[i] - arr[i - 1]
if d != diff: return False
return True