Problem Link

Description


Given an integer array sorted in non-decreasing order, there is exactly one integer in the array that occurs more than 25% of the time, return that integer.

 

Example 1:

Input: arr = [1,2,2,6,6,6,6,7,10]
Output: 6

Example 2:

Input: arr = [1,1]
Output: 1

 

Constraints:

  • 1 <= arr.length <= 104
  • 0 <= arr[i] <= 105

Solution


Python3

class Solution:
    def findSpecialInteger(self, arr: List[int]) -> int:
        N = len(arr)
        freq = N // 4
 
        for i in range(N - freq + 1):
            if arr[i] == arr[i + freq]:
                return arr[i]