Problem Link

Description


Given two arrays of unique digits nums1 and nums2, return the smallest number that contains at least one digit from each array.

 

Example 1:

Input: nums1 = [4,1,3], nums2 = [5,7]
Output: 15
Explanation: The number 15 contains the digit 1 from nums1 and the digit 5 from nums2. It can be proven that 15 is the smallest number we can have.

Example 2:

Input: nums1 = [3,5,2,6], nums2 = [3,1,7]
Output: 3
Explanation: The number 3 contains the digit 3 which exists in both arrays.

 

Constraints:

  • 1 <= nums1.length, nums2.length <= 9
  • 1 <= nums1[i], nums2[i] <= 9
  • All digits in each array are unique.

Solution


Python3

class Solution:
    def minNumber(self, nums1: List[int], nums2: List[int]) -> int:
        A = []
        
        for a in nums1:
            for b in nums2:
                if a == b:
                    A.append(a)
                    continue
                
                if a <= b:
                    A.append(a * 10 + b)
                else:
                    A.append(b * 10 + a)
            
        return min(A)