Description
You are given an integer array nums (0-indexed). In one operation, you can choose an element of the array and increment it by 1.
- For example, if
nums = [1,2,3], you can choose to incrementnums[1]to makenums = [1,3,3].
Return the minimum number of operations needed to make nums strictly increasing.
An array nums is strictly increasing if nums[i] < nums[i+1] for all 0 <= i < nums.length - 1. An array of length 1 is trivially strictly increasing.
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Example 1:
Input: nums = [1,1,1] Output: 3 Explanation: You can do the following operations: 1) Increment nums[2], so nums becomes [1,1,2]. 2) Increment nums[1], so nums becomes [1,2,2]. 3) Increment nums[2], so nums becomes [1,2,3].
Example 2:
Input: nums = [1,5,2,4,1] Output: 14
Example 3:
Input: nums = [8] Output: 0
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Constraints:
1 <= nums.length <= 50001 <= nums[i] <= 104
Solution
Python3
class Solution:
def minOperations(self, nums: List[int]) -> int:
n = len(nums)
res = 0
for i in range(1, n):
if nums[i] <= nums[i - 1]:
d = nums[i - 1] + 1
res += d - nums[i]
nums[i] = d
return res