Problem Link

Description


Given a list of folders folder, return the folders after removing all sub-folders in those folders. You may return the answer in any order.

If a folder[i] is located within another folder[j], it is called a sub-folder of it. A sub-folder of folder[j] must start with folder[j], followed by a "/". For example, "/a/b" is a sub-folder of "/a", but "/b" is not a sub-folder of "/a/b/c".

The format of a path is one or more concatenated strings of the form: '/' followed by one or more lowercase English letters.

  • For example, "/leetcode" and "/leetcode/problems" are valid paths while an empty string and "/" are not.

 

Example 1:

Input: folder = ["/a","/a/b","/c/d","/c/d/e","/c/f"]
Output: ["/a","/c/d","/c/f"]
Explanation: Folders "/a/b" is a subfolder of "/a" and "/c/d/e" is inside of folder "/c/d" in our filesystem.

Example 2:

Input: folder = ["/a","/a/b/c","/a/b/d"]
Output: ["/a"]
Explanation: Folders "/a/b/c" and "/a/b/d" will be removed because they are subfolders of "/a".

Example 3:

Input: folder = ["/a/b/c","/a/b/ca","/a/b/d"]
Output: ["/a/b/c","/a/b/ca","/a/b/d"]

 

Constraints:

  • 1 <= folder.length <= 4 * 104
  • 2 <= folder[i].length <= 100
  • folder[i] contains only lowercase letters and '/'.
  • folder[i] always starts with the character '/'.
  • Each folder name is unique.

Solution


Python3

class Solution:
    def removeSubfolders(self, folder: List[str]) -> List[str]:
        N = len(folder)
        folder.sort()
        res = [folder[0]]
 
        for i in range(1, N):
            last = res[-1] + "/"
 
            if not folder[i].startswith(last):
                res.append(folder[i])
 
        return res