Description
You are given an integer array nums
and an integer k
. You want to find a subsequence of nums
of length k
that has the largest sum.
Return any such subsequence as an integer array of length k
.
A subsequence is an array that can be derived from another array by deleting some or no elements without changing the order of the remaining elements.
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Example 1:
Input: nums = [2,1,3,3], k = 2 Output: [3,3] Explanation: The subsequence has the largest sum of 3 + 3 = 6.
Example 2:
Input: nums = [-1,-2,3,4], k = 3 Output: [-1,3,4] Explanation: The subsequence has the largest sum of -1 + 3 + 4 = 6.
Example 3:
Input: nums = [3,4,3,3], k = 2 Output: [3,4] Explanation: The subsequence has the largest sum of 3 + 4 = 7. Another possible subsequence is [4, 3].
Β
Constraints:
1 <= nums.length <= 1000
-105Β <= nums[i] <= 105
1 <= k <= nums.length
Solution
Python3
class Solution:
def maxSubsequence(self, nums: List[int], k: int) -> List[int]:
pq = []
for i, x in enumerate(nums):
if len(pq) == k:
heappushpop(pq, (x, i))
else:
heappush(pq, (x, i))
idx = [i for _, i in pq]
idx.sort()
return [nums[i] for i in idx]