Description
You are given a binary array nums.
You can do the following operation on the array any number of times (possibly zero):
- Choose any index
ifrom the array and flip all the elements from indexito the end of the array.
Flipping an element means changing its value from 0 to 1, and from 1 to 0.
Return the minimum number of operations required to make all elements in nums equal to 1.
Β
Example 1:
Input: nums = [0,1,1,0,1]
Output: 4
Explanation:
We can do the following operations:
- Choose the index
i = 1. The resulting array will benums = [0,0,0,1,0]. - Choose the index
i = 0. The resulting array will benums = [1,1,1,0,1]. - Choose the index
i = 4. The resulting array will benums = [1,1,1,0,0]. - Choose the index
i = 3. The resulting array will benums = [1,1,1,1,1].
Example 2:
Input: nums = [1,0,0,0]
Output: 1
Explanation:
We can do the following operation:
- Choose the index
i = 1. The resulting array will benums = [1,1,1,1].
Β
Constraints:
1 <= nums.length <= 1050 <= nums[i] <= 1
Solution
Python3
class Solution:
def minOperations(self, nums: List[int]) -> int:
N = len(nums)
change = 0
res = 0
for x in nums:
if change % 2 == x:
change += 1
res += 1
return res