Problem Link

Description


Given a string s and a string array dictionary, return the longest string in the dictionary that can be formed by deleting some of the given string characters. If there is more than one possible result, return the longest word with the smallest lexicographical order. If there is no possible result, return the empty string.

 

Example 1:

Input: s = "abpcplea", dictionary = ["ale","apple","monkey","plea"]
Output: "apple"

Example 2:

Input: s = "abpcplea", dictionary = ["a","b","c"]
Output: "a"

 

Constraints:

  • 1 <= s.length <= 1000
  • 1 <= dictionary.length <= 1000
  • 1 <= dictionary[i].length <= 1000
  • s and dictionary[i] consist of lowercase English letters.

Solution


Python3

class Solution:
    def findLongestWord(self, s: str, d: List[str]) -> str:
        d.sort(key = lambda x: (-len(x), x))
        
        for word in d:
            i = 0
            
            for c in s:
                if i < len(word) and c == word[i]:
                    i += 1
                
            if i == len(word): return word
        
        return ""