Problem Link

Description


Alice and Bob are playing a game on a string.

You are given a string s, Alice and Bob will take turns playing the following game where Alice starts first:

  • On Alice's turn, she has to remove any non-empty substring from s that contains an odd number of vowels.
  • On Bob's turn, he has to remove any non-empty substring from s that contains an even number of vowels.

The first player who cannot make a move on their turn loses the game. We assume that both Alice and Bob play optimally.

Return true if Alice wins the game, and false otherwise.

The English vowels are: a, e, i, o, and u.

 

Example 1:

Input: s = "leetcoder"

Output: true

Explanation:
Alice can win the game as follows:

  • Alice plays first, she can delete the underlined substring in s = "leetcoder" which contains 3 vowels. The resulting string is s = "der".
  • Bob plays second, he can delete the underlined substring in s = "der" which contains 0 vowels. The resulting string is s = "er".
  • Alice plays third, she can delete the whole string s = "er" which contains 1 vowel.
  • Bob plays fourth, since the string is empty, there is no valid play for Bob. So Alice wins the game.

Example 2:

Input: s = "bbcd"

Output: false

Explanation:
There is no valid play for Alice in her first turn, so Alice loses the game.

 

Constraints:

  • 1 <= s.length <= 105
  • s consists only of lowercase English letters.

Solution


Python3

class Solution:
    def doesAliceWin(self, s: str) -> bool:
        N = len(s)
        vowels = 0
        
        for x in s:
            if x in "aeiou":
                vowels += 1
 
        return vowels > 0