Problem Link

Description


Given a multi-dimensional array of integers, return a generator object which yields integers in the same order as inorder traversal.

multi-dimensional array is a recursive data structure that contains both integers and other multi-dimensional arrays.

inorder traversal iterates over each array from left to right, yielding any integers it encounters or applying inorder traversal to any arrays it encounters.

 

Example 1:

Input: arr = [[[6]],[1,3],[]]
Output: [6,1,3]
Explanation:
const generator = inorderTraversal(arr);
generator.next().value; // 6
generator.next().value; // 1
generator.next().value; // 3
generator.next().done; // true

Example 2:

Input: arr = []
Output: []
Explanation: There are no integers so the generator doesn't yield anything.

 

Constraints:

  • 0 <= arr.flat().length <= 105
  • 0 <= arr.flat()[i] <= 105
  • maxNestingDepth <= 105

 

Can you solve this without creating a new flattened version of the array?

Solution


TypeScript

type MultidimensionalArray = (MultidimensionalArray | number)[]
 
function* inorderTraversal(arr: MultidimensionalArray): Generator<number, void, unknown> {
    for (const element of arr) {
        if (Array.isArray(element)) {
            yield* inorderTraversal(element);
        } else {
            yield element;
        }
    }
};
 
/**
 * const gen = inorderTraversal([1, [2, 3]]);
 * gen.next().value; // 1
 * gen.next().value; // 2
 * gen.next().value; // 3
 */