Problem Link

Description


Given an integer array arr, return trueΒ if there are three consecutive odd numbers in the array. Otherwise, returnΒ false.

Β 

Example 1:

Input: arr = [2,6,4,1]
Output: false
Explanation: There are no three consecutive odds.

Example 2:

Input: arr = [1,2,34,3,4,5,7,23,12]
Output: true
Explanation: [5,7,23] are three consecutive odds.

Β 

Constraints:

  • 1 <= arr.length <= 1000
  • 1 <= arr[i] <= 1000

Solution


Python3

class Solution:
    def threeConsecutiveOdds(self, arr: List[int]) -> bool:
        N = len(arr)
 
        for i in range(N - 2):
            if arr[i] % 2 == arr[i + 1] % 2 == arr[i + 2] % 2 == 1:
                return True
        
        return False