Problem Link

Description


A trie (pronounced as "try") or prefix tree is a tree data structure used to efficiently store and retrieve keys in a dataset of strings. There are various applications of this data structure, such as autocomplete and spellchecker.

Implement the Trie class:

  • Trie() Initializes the trie object.
  • void insert(String word) Inserts the string word into the trie.
  • boolean search(String word) Returns true if the string word is in the trie (i.e., was inserted before), and false otherwise.
  • boolean startsWith(String prefix) Returns true if there is a previously inserted string word that has the prefix prefix, and false otherwise.

 

Example 1:

Input
["Trie", "insert", "search", "search", "startsWith", "insert", "search"]
[[], ["apple"], ["apple"], ["app"], ["app"], ["app"], ["app"]]
Output
[null, null, true, false, true, null, true]

Explanation
Trie trie = new Trie();
trie.insert("apple");
trie.search("apple");   // return True
trie.search("app");     // return False
trie.startsWith("app"); // return True
trie.insert("app");
trie.search("app");     // return True

 

Constraints:

  • 1 <= word.length, prefix.length <= 2000
  • word and prefix consist only of lowercase English letters.
  • At most 3 * 104 calls in total will be made to insert, search, and startsWith.

Solution


Python3

class TrieNode:
    def __init__(self):
        self.children = defaultdict(TrieNode)
        self.hasEnd = False
 
class Trie:
 
    def __init__(self):
        self.root = TrieNode()
 
    def insert(self, word: str) -> None:
        curr = self.root
        
        for x in word:
            curr = curr.children[x]
        
        curr.hasEnd = True
 
    def search(self, word: str) -> bool:
        curr = self.root
        
        for x in word:
            if x not in curr.children:
                return False
            
            curr = curr.children[x]
        
        return curr.hasEnd
 
    def startsWith(self, prefix: str) -> bool:
        curr = self.root
        
        for x in prefix:
            if x not in curr.children:
                return False
            
            curr = curr.children[x]
        
        return True
 
 
# Your Trie object will be instantiated and called as such:
# obj = Trie()
# obj.insert(word)
# param_2 = obj.search(word)
# param_3 = obj.startsWith(prefix)