Problem Link

Description


An array is considered special if every pair of its adjacent elements contains two numbers with different parity.

You are given an array of integer nums and a 2D integer matrix queries, where for queries[i] = [fromi, toi] your task is to check that subarray nums[fromi..toi] is special or not.

Return an array of booleans answer such that answer[i] is true if nums[fromi..toi] is special.

 

Example 1:

Input: nums = [3,4,1,2,6], queries = [[0,4]]

Output: [false]

Explanation:

The subarray is [3,4,1,2,6]. 2 and 6 are both even.

Example 2:

Input: nums = [4,3,1,6], queries = [[0,2],[2,3]]

Output: [false,true]

Explanation:

  1. The subarray is [4,3,1]. 3 and 1 are both odd. So the answer to this query is false.
  2. The subarray is [1,6]. There is only one pair: (1,6) and it contains numbers with different parity. So the answer to this query is true.

 

Constraints:

  • 1 <= nums.length <= 105
  • 1 <= nums[i] <= 105
  • 1 <= queries.length <= 105
  • queries[i].length == 2
  • 0 <= queries[i][0] <= queries[i][1] <= nums.length - 1

Solution


Python3

class Solution:
    def isArraySpecial(self, nums: List[int], queries: List[List[int]]) -> List[bool]:
        N = len(nums)
        A = [0] * N
        A[0] = 1
        res = []
 
        for i in range(1, N):
            v = 1 if nums[i - 1] % 2 != nums[i] % 2 else 0
            A[i] += v + A[i - 1]
        for a, b in queries:
            res.append(A[b] - A[a] == (b - a))
        
        return res