Description
Given a non-negative integer num, return true if num can be expressed as the sum of any non-negative integer and its reverse, or false otherwise.
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Example 1:
Input: num = 443 Output: true Explanation: 172 + 271 = 443 so we return true.
Example 2:
Input: num = 63 Output: false Explanation: 63 cannot be expressed as the sum of a non-negative integer and its reverse so we return false.
Example 3:
Input: num = 181 Output: true Explanation: 140 + 041 = 181 so we return true. Note that when a number is reversed, there may be leading zeros.
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Constraints:
- 0 <= num <= 105
Solution
Python3
class Solution:
    def sumOfNumberAndReverse(self, num: int) -> bool:
        N = len(str(num))
        
        for x in range(num, num // 2 - 1, -1):
            if x + int(str(x)[::-1]) == num:
                return True
        
        return False