Description
You're given strings jewels
representing the types of stones that are jewels, and stones
representing the stones you have. Each character in stones
is a type of stone you have. You want to know how many of the stones you have are also jewels.
Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
ย
Example 1:
Input: jewels = "aA", stones = "aAAbbbb" Output: 3
Example 2:
Input: jewels = "z", stones = "ZZ" Output: 0
ย
Constraints:
1 <=ย jewels.length, stones.length <= 50
jewels
andstones
consist of only English letters.- All the characters ofย
jewels
are unique.
Solution
Python3
class Solution:
def numJewelsInStones(self, J: str, S: str) -> int:
return sum([i in J for i in S])
Python
class Solution(object):
def numJewelsInStones(self, J, S):
"""
:type J: str
:type S: str
:rtype: int
"""
lst = []
for i in J:
lst.append(i)
count=0
for i in S:
if i in lst:
count+=1
return count