Description
Given two strings ransomNote and magazine, return true if ransomNote can be constructed by using the letters from magazine and false otherwise.
Each letter in magazine can only be used once in ransomNote.
Β
Example 1:
Input: ransomNote = "a", magazine = "b" Output: false
Example 2:
Input: ransomNote = "aa", magazine = "ab" Output: false
Example 3:
Input: ransomNote = "aa", magazine = "aab" Output: true
Β
Constraints:
1 <= ransomNote.length, magazine.length <= 105ransomNoteandmagazineconsist of lowercase English letters.
Solution
Python3
class Solution:
def canConstruct(self, ransomNote: str, magazine: str) -> bool:
mp = collections.Counter(ransomNote)
n = len(mp)
for word in magazine:
mp[word] -= 1
if mp[word] == 0:
n -= 1
if n == 0: return True
return False