Description
Table: Accounts
+-------------+------+ | Column Name | Type | +-------------+------+ | account_id | int | | income | int | +-------------+------+ account_id is the primary key (column with unique values) for this table. Each row contains information about the monthly income for one bank account.
Write a solution to calculate the number of bank accounts for each salary category. The salary categories are:
"Low Salary": All the salaries strictly less than$20000."Average Salary": All the salaries in the inclusive range[$20000, $50000]."High Salary": All the salaries strictly greater than$50000.
The result table must contain all three categories. If there are no accounts in a category, return 0.
Return the result table in any order.
The result format is in the following example.
Example 1:
Input: Accounts table: +------------+--------+ | account_id | income | +------------+--------+ | 3 | 108939 | | 2 | 12747 | | 8 | 87709 | | 6 | 91796 | +------------+--------+ Output: +----------------+----------------+ | category | accounts_count | +----------------+----------------+ | Low Salary | 1 | | Average Salary | 0 | | High Salary | 3 | +----------------+----------------+ Explanation: Low Salary: Account 2. Average Salary: No accounts. High Salary: Accounts 3, 6, and 8.
Solution
MySQL
# Write your MySQL query statement below
select 'Low Salary' as category, count(*) as accounts_count
from accounts a
where a.income < 20000
UNION
select 'Average Salary' as category, count(*) as accounts_count
from accounts a
where a.income >= 20000 and a.income <= 50000
UNION
select 'High Salary' as category, count(*) as accounts_count
from accounts a
where a.income > 50000